12p^2-6p-6=0

Solution for 12p^2-6p-6=0 equation:

12p^2-6p-6=0

a = 12; b = -6; c = -6;
Δ = b2-4ac
Δ = -62-4·12·(-6)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-18}{2*12}=\frac{-12}{24}
=-1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+18}{2*12}=\frac{24}{24}
=1
$